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Divide the impedance by the line’s own impedance first. On a 50-ohm line, a load of 50 + j50 ohms is z = 1 + j1: plot it where the circle marked 1 meets the arc marked +1. Positive reactance, inductive, is in the upper half and negative, capacitive, in the lower. The centre is z = 1, a perfect match; the left end of the line across the middle is a short circuit and the right end an open circuit.

1 + j1matchshortopen
On a 50-ohm line, 50 + j50 ohms is z = 1 + j1: where the circle marked 1 meets the arc marked +1, in the upper (inductive) half.

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